2x^2=(x/2)^0.5

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Solution for 2x^2=(x/2)^0.5 equation: 


D( x )

x/2 < 0

x/2 < 0

x/2 < 0

1/2*x+0 < 0 // - 0

1/2*x < 0 // : 1/2

x < 0/1/2

x < 0

x in <0:+oo)

2*x^2 = (x/2)^0.5 // - (x/2)^0.5

2*x^2-(x/2)^0.5 = 0

2*x^2-(1/2)^0.5*x^0.5 = 0

x^0.5*(2*x^1.5-(1/2)^0.5) = 0

2*x^1.5 = (1/2)^0.5 // : 2

x^1.5 = ((1/2)^0.5)/2

x = (((1/2)^0.5)/2)^(1/0.5)

x^0.5 = 0

1*x^0.5 = 0 // : 1

x^0.5 = 0

x = 0

x in { (((1/2)^0.5)/2)^(1/0.5), 0 }

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